(x+3)^2=3x+7

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Solution for (x+3)^2=3x+7 equation: 



(x+3)^2=3x+7

We move all terms to the left:

(x+3)^2-(3x+7)=0

We get rid of parentheses

(x+3)^2-3x-7=0

We add all the numbers together, and all the variables

-3x+(x+3)^2-7=0

We move all terms containing x to the left, all other terms to the right

-3x+(x+3)^2=7

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